In general, it should be noted that the cheaper the product the more likely it is to be of poor quality. You should consider your budget and stretch it as much as possible to get the best possible converter. So applying a resistor will diminish the voltage of the circuit. That should mean that an appropriately sized resistor could simply be placed in the path of a 12V circuit, converting it to 5v. E.g., in an LM2596-based adjustable DC-DC converter, it was “forgotten” to install a capacitor between the output and sense-input (thereby multiplying the output ripple with a factor related to the difference between output voltage and sense-voltage of 1.23V(Cff in LM2596 datasheet: https://www.onsemi.com/pub/Collateral/LM2596-D.PDF). However, adding a 15nF capacitor did not solve all of the ripple (I would consider a ripple up to 100mV acceptable).

I’m using ‘Fine’ for a hobby solar-project, charging my phones etc. What I can’t figure out with my ‘Fine’ is this: My input is 6.5 V/350 mA, this will result in 4.85 V/240 mA after ‘Fine’ is done and having a charging phone connected, so it should draw some juice.. Now, maybe I’m just overseeing some basic physics here.. Do you think I do have a faulty ‘Fine’?Higher switching frequency will mean less ripple on the output (more accurate voltage/current) but causes more overhead due to switching, which reduces the efficiency a bit. A load resistor or output circuit is a must at output end while implementing or testing it in a circuit to prevent zener diode from getting burn. All the circuits have different performance. The voltage divider circuit is not recommended for use in the high current application as it has a low output current and lower efficiency. LM7805 12v to 5v converter: The data sheet for this converter says that the turn-on time, rise time, and delay time are all in the sub 40ns range--so it should work fine, right?

I made an account just to ask this question, as it has been driving me crazy. For some reason, when I have 3.3V on the LV and 5V (actually around 5.5V) on the HV, the signals coming out of the HV end are all around 2.6V. Does anyone have some suggestions to fix this?

The project i am working includes connecting the various sensor and control signals between a 5 volt - does not work with the other digital level shifter, to a pi pico. Excellent and useful product, but I require more than 4 conversion lines. Although I can use 2 of these, I still prefer more than 4 channels on a single board, like the following very similar product: You can make a 12V to 5V converter yourself. This isn’t advisable unless you know what you are doing. The alternative is to buy one. But, there are many different styles available. It’s important you choose a type that suits your needs. The below image showing Voltage regulator IC without Heat-Sink and with a heat-sink. Sometimes heat-sinks are sold separately. Please ensure to connect heat-sink properly with conducting paste applied for high current applications.

This circuit is a voltage divider schematic. You can design it for the required ‘output voltage’ by using this formula:adjustable regulators haven’t been tuned to a single output voltage output, that’s why at these very light loads they have lower efficiency. This is a result of being much more universal devices.